x^2+74x-798=0

Solution for x^2+74x-798=0 equation:

x^2+74x-798=0

a = 1; b = 74; c = -798;
Δ = b2-4ac
Δ = 742-4·1·(-798)
Δ = 8668
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8668}=\sqrt{4*2167}=\sqrt{4}*\sqrt{2167}=2\sqrt{2167}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(74)-2\sqrt{2167}}{2*1}=\frac{-74-2\sqrt{2167}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(74)+2\sqrt{2167}}{2*1}=\frac{-74+2\sqrt{2167}}{2}
$